Recent content by filterwin9

solved

for Q=Ay , i gt A= (b)(0.5h - y) , y = y , so Q = (b)(0.5h - y)(y) , eventually , i gt τ = (V)(Q)/ (I)(b) = (V)(b)(0.5h - y)(y) / Ib = (V)(0.5h - y)(y) / I which is different with the author 's working , am i wrong ...

Homework Statement where V = total shear force at the location in question; Q = statistical moment of area; t = thickness in the material perpendicular to the shear; I = Moment of Inertia of the entire cross sectional area. based on this formula , the shear stress is max at the neutral axis of...