Thanks for the help guys, sorry about the lateness, I'm all over the place getting ready for Uni.
Would you have any tips on getting the most out of what you see / hear, such as the active listening idea?
Hello,
Just a bit of background, I'm preparing to go to Durham University in the UK, (I'm a UK student, did GCSEs, Alevel etc. Only mention in the vague chance there may be someone who has studied at Durham / studied in the UK and can give me more detailed advice / information)
I am really...
I have a rather simple question which I can't seem to find an answer to
If I have two balls, one denser than the other, but of same volume, and let them float on water, would the denser one float deeper in the water?
The water is the same and the density of the two balls are less than the...
I just want to stress I'm not so sure on the physics but I feel it is just a error in standard form
Your notes give you the answer 1.54MN/m2, which is 1.54 Mega nm2 which is 1.54x106 N/m2 or 1,540,000 n/m2
Your answer is 154.3x104 N/m2which is 154.3x10,000 which is 1,543,000 N/m2
Unfortunately both of my scales are digital and tend to blur/crash when the change is sudden
From what I can tell for number three is that when I am stationary my weight is constant. When I unlock my knees the reading decreases from equilibrum and then increases when I start to stop and slow...
I'm not sure what you mean by that statement, do you mean the spring or the man?
I think the first thing you would do is then decelerate downwards, meaning a reduction in the reading on the weight before you then start the motion of jumping upwards
When he is accelerating downwards, the...
For Number 2
The weight of the man would increase as he hits the scales but then as he becomes stationary the spring becomes less depressed and therefore shows a smaller weight (F=-kx). I'm unclear as to whether the weight shown should actually decrease for a while because there needs to be a...
Yeah, from there you should be able to get your answer of 281m (which is correct, books can be prone to errors sometimes though)
Remember in free fall that the acceleration would be -9.81ms^2
Concentrate on only the vertical component of acceleration and displacement etc.
You have a resultant acceleration in a given direction, find the acceleration in the direction you need
For number 2, should the weight actually decrease then because the man is accelerating downwards (during the impact stage). When you are at rest, then your weight should be correct as you are stationary.
For number 3, I can't see why the weight of the man should not return to normal after he...
Homework Statement
Draw graphs of weight against time for the following
1) man stands on scale very gently and then gets off again very gently
2) man jumps onto scales and then jumps off again
3) man stands on scale and let's his knees unlock so that he drops, then stops.
For each of...