Recent content by fisher garry

Where does it fail in the first post. And why does it fail?

$$\frac{d^2B}{dx^2}c^2=\frac{d^2B}{d t^2}$$ $$\textbf{B}\frac{d^2 sin[2 \pi f \frac{x}{c}]}{dx^2}c^2=\textbf{B}\frac{d^2sin[2 \pi f t]}{d t^2}$$ $$-4 \pi^2 f^2 \frac{1}{c^2}\textbf{B}sin[2 \pi f \frac{x}{c}] c^2=-4 \pi^2 f^2\textbf{B} sin[2 \pi f t]$$ So it seems to be a solution? As for...

:-p This is taken from introduction to electrodynamics by Griffiths which the rearrangment of the maxwell equations are taken from. I will rewrite what it says there if it is ok: Suppose we have some charge and current configuration which at time t, produces fields E and . In the next...

Ok. Thanks for feedback :) If I could ask: I have a setup here with EM waves coming out of an object I would believe. I want to use the divergence theorem to find a solution for the frequency. How would the direction of the EM waves be in order to be able to use this setup? Thanks :)

Sorry. I will write it out. Ok I could ask: Show me the values for the frequency f that is given in the equation I ended up with in my first post. Here is one attempt: I did ponder on solving the equation with the charge radius. Since I have been told that the charge radius is where electrons...

Sorry. Same as in my last post really. I was looking for a equation that would solve the frequency in the EM wave equation: $$B=\textbf{B} \sin [2 \pi ft]$$

Sorry. I guess my qestion would be: I did end up with an equation where R, the radius, and f, the frequency, are variables. But it did not yield any solutions. (look at the last attachment part for this). The problem for me is that I can't seem to see where there is an error in the calculations...

$$\textbf{F} \cdot d\textbf{l}=q(\textbf{E}+\textbf{v} \times \textbf{B})\cdot \textbf{v} dt$$ If we denote $$q=\rho d \tau$$ and $$\rho \textbf{v}=\textbf{J}$$ $$\frac{dW}{dt}=\int_{V} (\textbf{E} \cdot \textbf{J}) d \tau.$$ From maxwell law's $$\textbf{E} \cdot \textbf{J}=\frac{1}{\mu _0}...

the first energy relation deals with an electron revolving with velocity in the 1s shell and has energy given as ##8 \frac{V}{\mu _0} \textbf{B}_{0}## The second energy relation deals with the same energy being given out from the electron and instead of a revolving electron in an orbital we...

This is taken from this site https://www.quora.com/What-happened-to-the-Classical-Electron-Radius-at-2-8E-15-m-Does-it-signify-anything-in-modern-terms

I guess I could write it down in tex:smile: ##\textbf{F}\cdot d \textbf{l}=q (\textbf{E} +\textbf{v}\times\textbf{B})\cdot \textbf{v}dt=q \textbf{E} \cdot \textbf{v}dt## current density is defined as ##\textbf{J}=\rho \textbf{v}## ##\textbf{F}\cdot d \textbf{l}=\frac{q}{\rho} \textbf{E} \cdot...

I have been working a bit more and this time I ended up with some relations that could have the right numbers. So hopefully it is ok that I post this as I am not sure where else I would post. in the theory in the top of this post there is also a volume integral which starts the derivation...

Ok. Thanks for the answer. Yes most of this is something I have made myself so a reference is of course not available. I did assume that half of the energy of one photon was absorbed from a half cycle. Perhaps that is wrong. I also wondered when I used the theory of the radiation pressure from...

I think I understand. Let me change the scenario. You have a circular current coil and apply an external B field. I will rewrite the relations of the kinetic energy produced: When the coil has turned 90 degrees it reaches equilibrium and deaccelerates to 0 velocity. Let's assume hypotetically...

I understand what you meant now:) That was one of the things I wondered about. In Tipler and Mosca they use the following equation. I Will add some more of the theory just in case there are any relations. This is the theory that I used for the white middle part above: The poynting vector...