the PE is the only energy it has before released correct. I don't know how this will help me find velocity. I am really looking for the correct formula to use here.
Two balls of masses Ma=40g and Mb=60g are suspended as shown in the picture in your text. The lighter ball is pulled away to a 60 degree angle with the verticle and released.
a) What is the velocity of the lighter ball before imapct?
b) What is the veloctity of each ball after the elastic...
Consider a frictionless track as shown in the diagram below. A block of mass m1=8.00kg is released from point A at a height of 5.00m. It collides with a block of mass m2=10.0 kg, initially at rest, at point B. The two blocks stick together. Determine the final velocity of the blocks...
A child in a boat throws a 6.40kg package out horizontally with a speed of 10m/s. Calculate the velocity of the boat immediately after, assuming it was initially at rest. The mass of the child is 26.0kg and the mass of the boat is 45.0kg. Ignore water resistance.
Relevant equations
MV1 +...
Well that does not help me determine how to fix this problem. Should the velocity used in the problem be found from (MV1+MV2) = M(1+2)V(1+2) and solve for V1+2?
A Skateboarder with mass m1=48kg runs at 6.8m/s and jumps onto her skateboard with mass m2=2.9kg which is at rest at the bottom of a curved ramp. When the skateboarder lands on the board, how high does she and the skateboard go?
Relevant equations
w=[1/2(MVf^s)-1/2(MVi^2)]+[(MGHf-MGHi)]...
Formulas
Are there any formulas i should know for this particular problem. The thing that confuses me is that I know how to figure friction work, but i do not know how to find this with an angle involved.
Suppose the ski patrol lowers a rescue sled and victim 30m down a slope at a constant speed as shown below. The victim and sled have a total mass of 90kg. The angle of the slope is 60 degrees.
If the coefficient of friction is 0.100.
a) Find the work done by friction as the sled moves down...