Recent content by FizzixIzFun

Homework Statement If you have a rod that is pivoted at one end with a mass of 4 kg and a length of 24 m and the other end has a sphere attached to it that is 4 kg and has a radius of 1.5 m, what is the center of mass?Homework Equations MXcm= m1x1 + m2x2The Attempt at a Solution I think that...

I've got it now. Thanks everybody.

Well, I don't know what to say except that that was the answer my teacher gave me.

Homework Statement The force constant of a spring is 400 N/m and the unstretched length is .65 m. A 2.0 kg block is suspended from the spring. An external force slowly pulls the block down, until the spring has been stretched to a length of .78 m. The external force is then removed, and the...

Thank you so much for the help. I've got it now.

Here's what I've come up with. Using m1gh=(1/2)m1v1^2, I solve for the velocity of m1 right before the collision. Then, I do m1v1=m2v2 and solve for v2 which would be the velocity of the block immediately after the collision. I then do (1/2)m2v2^2=m2gh and solve for h which gives me the...

OK, I'm lost. I don't know what to do.

Ok, I think I got it. (A.) I use (365)gh = (1/2)(480)v^2 and solve for v. (B.) I use (1/2)(480)v^2= (480)gh and solve for h. Is that correct?

Ok, I think I got it. (A.) I use (365)gh = (1/2)(480)v^2 and solve for v. (B.) I use (1/2)(480)v^2= (480)gh and solve for h. Is that correct?

Momentum homework problem due this Tuesday Homework Statement Here's the question: The surfaces are frictionless. The tracks are 60 degrees from horizontal. A 365 kg mass is released from rest on a track at a height 4.2 m above a horizontal surface at the foot of the slope. It collides...

Oh, I see. I need to use R=([V^2]sin(2[theta])) / g. So it would look like 14.2 = ([V^2]sin(2[theta])) / 9.81 where V is the answer to #1 and I would solve for theta. Right?

Ok, I'm lost. What should I do? Why doesn't he hit the bottom of the gorge?

78 is the depth of the gorge so that you can figure out the amount of time it takes him to get from the point where he jumps to the point where he lands. it's from the kinematic x=x(initial) +V(initial)t + .5at^2

1)Wiley Coyote is chasing the roadrunner yet again. While running down the road, they come to a deep gorge, 15 m straight across and 78 m deep. The roadrunner launches itself across the gorge at a launch angle of 12 degrees above the horizontal, and lands with 2.4 m to spare. The acceleration...