What Is the Center of Mass for a Rod with a Sphere Attached?

Click For Summary
SUMMARY

The center of mass for a system consisting of a 4 kg rod and a 4 kg sphere attached at one end can be calculated using the formula MXcm = m1x1 + m2x2. Given the rod's length of 24 m and the sphere's radius of 1.5 m, the center of mass is determined by balancing the torques around the pivot point. The equilibrium condition requires that the clockwise torque equals the anticlockwise torque, allowing for the calculation of the center of mass location along the rod.

PREREQUISITES
  • Understanding of torque and equilibrium in physics
  • Familiarity with the concept of center of mass
  • Basic knowledge of mass distribution
  • Ability to interpret and create diagrams for physical systems
NEXT STEPS
  • Study the principles of torque and equilibrium in static systems
  • Learn how to calculate the center of mass for composite objects
  • Explore the use of diagrams in solving physics problems
  • Review examples of center of mass calculations involving rods and attached masses
USEFUL FOR

Students in physics, particularly those studying mechanics, as well as educators and anyone seeking to understand the principles of center of mass in physical systems.

FizzixIzFun
Messages
14
Reaction score
0

Homework Statement


If you have a rod that is pivoted at one end with a mass of 4 kg and a length of 24 m and the other end has a sphere attached to it that is 4 kg and has a radius of 1.5 m, what is the center of mass?

Homework Equations


MXcm= m1x1 + m2x2

The Attempt at a Solution


I think that the center of mass should be where the sphere attaches to the rod, but I feel like that isn't right.
 
Last edited:
Physics news on Phys.org
The centre of mass will be the middle of the total distance where the total torque is in equilibrium.

That being said, Once you figure out the torque of one end (going clockwise), you can equate it to torque at the other end (going anticlockwise, so the rod and sphere is static) and the distance can be evaluated, which will be the distance from the end to the middle.

A diagram really helps.
 

Similar threads

Replies
10
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 62 ·
3
Replies
62
Views
14K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
17
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 19 ·
Replies
19
Views
5K