Recent content by flgdx

could you pls show me how you got that equation?

so since (sinθ)^2 + (cosθ)^2 = 1, I solved for sinθ and got sqrt(1 - (cosθ)^2). Then I subtituted it into the equation 3cos(θ) + 1.595*sin(θ) = 3.114 and solved for θ.

Homework Statement what's the best way to solve this equation: 3cos(θ) + 1.595*sin(θ) = 3.114 Homework Equations (sinθ)^2 + (cosθ)^2 = 1 The Attempt at a Solution I tried using the identity above to solve this equation and ended up with cosθ = +/- 1.0526.

oh and one last question pls. Why does cosine law work for 2/4 when solving for R but when I try to use sine law I get a different value?

Oh okay. I see where my fault lies now. It's because I assumed that R is completely horizontal with an angle of 0 degrees in reference to the dotted lines in reference to the first picture in problem 2/4. Thank you so much!

Oh sorry, I meant why does Rcos(20) not give us the projection for 2/4?

Yes sorry! I meant to say the a axis on problem 2/20. Also for 2/4, I was talking about the b-component of the 100N Force. Sorry I made this post before going to bed hence the number of mistakes. Let me clear up my question since it sounds a bit confusing. So for problem 2/20, the...

Homework Statement What's the projection of the resultant force onto an said axis? Homework Equations Sine Law, Cosine Law The Attempt at a Solution For problem 2/20, the projection onto the b axis was found by multiplying the resultant force by the cosine of 30 degrees. Why does this method...