Recent content by FLgirl

You are so knowledged. Tell me more tips to get good at chemistry.

Not really but if people were more inclined to solve the problem as an example, it would make learning go a lot quicker.

33 / 58.12 = 0.567 176 x 0.567 = 99.7

Oh right! How would I solve it then?

Thanks for answering... but why would you even need to know that to figure out how much CO2 was produced? Isn't it right there

1. What mass of butane in grams is necessary to produce 1.5 x 10^3 kJ of heat? What mass of CO2 is produced? C4H10 + 13/2 O2 --> 4 CO2 + 5 H2O Heat of reaction = -2658 kJ 2. 3. Mass of butane = 33g Mass of CO2 = 176.04g <-- This is wrong and the right answer is 99g CO2...

sweet, thanks

Thanks tiny tim :) This is what I got: (-310 J) + (7.6J) = 302.4 J = -3 x 10^2 J

1. Reacting 50 mL of H2(g) with 50 mL of C2H4(g) produces 50 mL of C2H6(g) at 1.5 atm. If the reaction produces 3.1 x 10^2 J of heat and the decrease in volume requires the surroundings do 7.6 J of work on the gases, what is the change in internal energy of the gases? 2. Change in...

Considering you didn't answer my question... how does that explain anything?

How do you do that... why are chemists so cryptic

1. Will the recorded temperature change for an exothermic reaction performed in a glass calorimeter be greater or less than that in a styrofoam coffee cup calorimeter? Assume glass to be a better conductor of heat than styrofoam. Please explain

1. To determine whether a shiny gold rock is actually gold, a student decides to measure its heat capacity. She first weighs the rock and finds it has a mass of 4.7g. She then finds that upon absorbtion of 57.2 J of heat, the temperature of the rock rises from 25 degree Celsius to 57 degree...

1. An acid-base neutralization reaction is exothermic. For the measurement of the enthalpy of neutralization, for the reaction, heat is inevitably lost to the calorimeter (beaker or styrofoam cup). How will this unaccounted for heat loss affect the reported value for the enthalpy of...

This forum really is so unhelpful.