Recent content by fliinghier

because each rope is at 45 degrees. I'm sorry but i need to go for now. i hope you can get it and if not, i'll be back in a few hours.

almost. you are calculating the distance vertically from the top of the tree.

the x and y on the US are equal to each other. the x and y on the LS are different, but equal to themselves.

the tension in the strings is at a 45 degree angle. this means the x and y components are equal. no, the x's are not both equal to each other

no. if you look closely, the horizontal line is the distance across the ravine, and the 2m is your rope before you go. what are the other two lines? hint: the hypotenuse in the picture is 2m

that doesn't mean they are the same. the mass pulls more on the top string because the mass is below it, so the top string fights gravity and the lower string in the y direction. the x and y of both strings are ___?

i believe that 8% is the tangent of the angle. the coefficient of friction is mu, and for most cars should be between .6 and .8

is the rope vertical when you get across?

they are the same direction, but why are they equal? what is equal?

no, it is. hoever there are an infinite number of possibilities for the velocities of both objects. they are not necessarily equal. something else is conserved, and using it will get you an answer.

what does US X+LS X equal?

no, x is your height. the width of the ravine is perpendicular to the height and the length of the rope when it's hanging straight down.

actually it is an elastic collision. the objects rebound off of one another, they don't stick together.

there is no velocity in the end either. there are only three forces, and you need to draw them in. you already said that Fg is straight down, while Fn is perpendicular to the grade and Ff is parallel.

2m in your problem is the rope