Recent content by fr33d0m

The function you specift is given by the following formula: Jalpha=w+(alpha)^2/w. Hence j2i=3+4/3 and j2i = 3-4/3. Substituting this into the standard equation of an ellipse for a^2 and b^2 and rearranging gives the required formula. Does this help?

Hi All Think I've cracked part (i) and (ii). However, I'm stuch on part (iii). I think I need to use the Inverse Function Rule somehow to get the function stated but when I do, it doesn't give the answer. Can someone please help? The inverse function rule states that f (z)'=1/1-1/(f(z))^2...

Hi All I have one final question that's related to flow problems with obstacles. Any help would be greatly appreciated as I am finding fluid flows extremely difficult. "Examinations are formidable even to the best prepared, for the greatest fool may ask more than the wisest man...

Hi All I'm having some problem with this question and was hoping that someone could help me with it. I think I have the first two bits but the rest I'm totally stuck For part (ii) I have the complex potential function as (3x^2)/2 - (3y^2)/2 +6y and the stream function as x(3y-6). Is this...