Recent content by Frankie715

I THINK I figured it out, but I am not sure. I will pick up where I left off and leave it to you guys to tell me if I did it correctly. A'B'C' + ABC' + A'B= A'(B+B'C') + ABC' = A'(B+C') + ABC' = A'B + A'C' + ABC' = B(A' + AC') + A'C' = B(A' + C') + A'C' = A'B + BC' + A'C' This final...

Homework Statement A'B'C' + ABC' + A'BC + A'BC'. The ' denotes a bar over the previous letter. Homework Equations Simplification Rules The Attempt at a Solution C' (A'B' + AB) + A'B(C+C') C' (A'B' + AB) + A'B ... or like so: A'B'C' + ABC' + A'B Is it possible to simplify...

Anyone have any idea what I am doing wrong? I have a test on this tomorrow and would like to know how to do this (If I am doing it incorrectly). Thanks

I got a magnitude of 13.4 for part B, but it is saying 8.49. What am I doing wrong? B) -A-B+C -6i + 12j sqrt(36+144)=13.4

Woops, I thought you were referring to the second part of part A to find the direction of the vector. I haven't begun part B yet. I will do it now to see if it matches the back of the book.

Yeah, For B) I did arctan(-2/2) which is -45 degrees and the book says its 63.4 degrees

Homework Statement Consider the three displacement vectors A=(3i-3j) m B=(i-4j) m C=(-2i+5j) m Use the component method to determine (a) the magnitude and direction of the vector: D= A+B+C and (b) the magnitude and direction of: E=-A-B+CHomework Equations The Attempt at a Solution I did...

I got h on the top. (sqrt (h + 121)) h + 11h on bottom. Is that correct?

Ok, let me figure this out. So I multiply the numerator and the denominator by sqrt (121+h)+11?

1) I got 11 out of the square root of 121 which cancels with the other -11. Confused about the remaining h. 2) I was confused at x = 4. Are my current 3 answers correct?

Homework Statement 1) 2) Homework Equations The Attempt at a Solution 1) I have done plenty of these, but this one is stumping me. I tried plugged in 0 approach for h and I got 11-11=0. With h on the bottom as 0. I know this isn't the right answer. I also know the limit does exist. If...