Recent content by Fraqtive42

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    Non-constant index of refraction due to layered material.

    The refractive index and \theta2 are related through Snell's Law.
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    Non-constant index of refraction due to layered material.

    If the material is layered infintesimally so that the index of refraction is proportional to the y, which I stated in the problem, then y is related to \theta2 because the index of refraction is related to \theta2
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    Non-constant index of refraction due to layered material.

    But because y is a function of time, that also makes \theta_{2} a function of time.
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    Non-constant index of refraction due to layered material.

    My work: So far I know that v=\frac{c}{n_{2}} is the speed of the light beam, which is also equal to v=\frac{dy}{dt}. So a differential equation to solve would be \frac{dy}{dt}=\frac{c}{n_{2}}
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    Generalization of infinite product problem

    I think that I have made my proof on the assumption that for any functions satisfying these conditions, \prod_{j=1}^{N}(f(j)-1)\leq\prod_{j=1}^{N}f(j) for any N\in\mathbb{N}. I don't see why f(n)=n+1 is an exception though.
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    Non-constant index of refraction due to layered material.

    A ray of light travels through a medium with an index of refraction n_{1} and strikes an layered medium such that the index of refraction is n_{2}=ky+1 where y is the depth of the medium and k is a constant. If it hits at an angle of \theta_{1} with respect to the normal, find the angle...
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    Generalization of infinite product problem

    Hmm... that is weird. My proof had some kind of error in it...
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    Generalization of infinite product problem

    You are saying that f(n)=n+1 doesn't work?
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    Generalization of infinite product problem

    Prove that \prod_{j=1}^{\infty}\left(1-\frac{1}{f(j)}\right)>0 for all f:\mathbb{N}^{+}\to\mathbb{R}^{+} which satisfy f(1)>1 and f(m+n)>f(m), where m,n\in\mathbb{N}^{+}. I found the problem "Prove that \prod_{j=1}^{\infty}\left(1-\frac{1}{2^{j}}\right)>0" and felt the need to make a...
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