Recent content by freddie_mclair

Ideal ignition corresponds to the condition of steady state power balance in the plasma assuming negligible heat conduction losses and no external heating, considering only Bremsstrahlung losses. Therefore, no losses transport losses due to heat conduction which are normally quantified by...

I've been trying to calculate the ideal ignition temperature for a 50-50% Deuterium-Tritium (D-T) reaction. In the literature this value is ##4.4##keV and I'm getting ##5.2##keV. Here's how I'm carrying out my calculations. This value can be calculated by making the alpha particle heating...

Thanks mfb, and PeroK. To conclude: energy release in this specific fusion reaction can be totally kinetic (shared the n and ) or kinetic + EM radiation.

No, why? I asked Hill where are the gamma rays in the reaction I described.

For this specific reaction I mentioned it is just Deuterium + Tritium, there are no gamma rays, just an alpha particle and a neutron. But in several places it is indicated that, apart from the reaction products, there is also an energy release, like for example here.

what would be the correct formulation then? and what amount of radiation would that be in terms of energy?

I agree with the kinetic energy of the products, but where are the gamma rays? What I understand is that the 17.6MeV are just split into the kinetic energy of the neutron by ##KE_n=\Delta m c^2 \frac{m_{\alpha}}{m_{\alpha}+m_n} ## and the rest to the alpha particle ##KE_{\alpha} = \Delta m c^2 -...

Hi, I have a fundamental (and maybe silly question) but I couldn't find a proper answer anywhere yet: For example, for a nuclear fusion reaction of Tritium (T) and Deuterium (D), we get an alpha particle (##\alpha##) a neutron (n) and energy release due to the mass difference ##\Delta...

What are the dimensions and material properties of the pipe? Also, to which bending radius do you need? What have you worked out up to now? In order to have a proper insight of the results it is better to understand well the theory and also its limitations instead of just “using the formulas”.

For a pipe, you can define ##b(x)=\sqrt{(R_o^2-R_i^2)-x^2}##, where ##R_o## is the outer radius and ##R_i## the inner radius.

Hi, try to use the same method I described above. You just need to adapt the cross-sectional geometry of your beam, i.e., redefine ##b(x)## for a pipe and, of course, the mechanical properties of the material. Then apply the steps I've defined in this post.

I have measurments of Helium at room temperature across some piping. We have set different mass flows, while always keeping the inlet pressure constant and then we measured the pressure in the outlet. With this we have the pressure drop at different mass flows. Now, I would like to extrapolate...

Hi, I have some measurements for pressure drop of Helium at room temperature and I would like to scale it to other temperatures. Taking into account that, i) the flow is turbulent, ii) the pressure drop, ##\Delta p##, happens always in the same piping and iii) there is only variation on the...

Hi, are the constants ##C_{10}## and ##C_{01}## defined in the same way in both books?

Hi, I never dealt directly with hyperlastic materials, but a nice book that I came across some years ago had a chapter dedicated to hyperelasticity. The book is this one: Notes on Continuum Mechanics It is very dense from the mathematical point of view, but it might help! It presents not only...