You can graph it on any graphing calculator and use the ISECT (intersect) function to find where they interstect, and that's your x value solution.
So you'd have:
y1 = cosx
y2= x/2 -1
Yes, I think I got it. The tension is equal to the weight of the hanging block (22 N), since hte other block is resting on the table.
It's in equilibrium, so a=0, so the whole term on that side of the equal sign becomes 0. Then T=mu * m (of Block A and C) * 9.8, then solve for the mass of Block C.
Well, in order for Block A *not* to move, the the frictional force on Block A must be equal to the tension right?
I redid the work for the acceleration and tension.
T = (Mmg + mF) / (M + m) M=4.489 kg m=2.245 kg
The tension (not taking Block C into account yet) is 17.6 N.
Set this equal...
Here's a pulley problem that has got me stopped; I'd appreciate any help that's offered.
There are two blocks, A (44 N) and B (22 N) connected via a rope that stretches over a pulley. Block A is resting on a table, and block B is hanging over the edge. Block C is positioned on top of Block A...