Recent content by Freyth

It's clear to me now. Thank you so much dynamicsolo, your help is much appreciated!

"In a nuclear system, the total energy would be the mass-energy of the constituents (ultimately the quarks) plus the mass-energy of the 'chromodynamic' force attracting them. When the negative mass-energy of this attractive force exceeds the positive mass-energy of the quarks, the nucleus is...

After further reading. I realized that the term "constant phase difference" actually means that the 2 waves at the point, no matter the period, will always be in phase/ antiphase. Unlike incoherent light sources which has random emission of light waves, thus constant phase difference is not...

Young's double slit experiment produces regular intervals of bright fringes and dark fringes. The bright fringes happen when the 2 sources of wave are in phase and superimpose while the dark fringes are produced when the 2 waves are in antiphase and vectorially cancel each other out. However...

I was thinking about it and thought if the separate mass of protons and neutrons included the "chromodynamic" force and is left out in the mass of the nucleus. Thereby obtaining the binding energy by finding the difference in mass. Which also explains why separate protons and neutrons have a...

Thanks, I understood that (most of the parts anyway), except this. Why is the sum of the masses of the individual constituent nucleons more than the mass of the nucleus itself? Following that, why is the "mass deficit" = binding energy of the nucleus? How is it related to what you posted -...

I believe I have got #3 of my last post. If the binding energy of the "products" is more than the binding energy of the "reactants" it basically means that the BE (binding energy), of the "products" is more negative than the BE of the "reactants". Therefore, the difference is actually the...

With reference to the first part, the mass-energy of the constituents would be the positive kinetic energy and the mass-energy of the attractive force would be the negative potential energy. So, when the mass-energy of the attractive force exceeds the mass-energy of the constituents, the...

My textbook (notes rather) indicates that the energy released in a nuclear fission and fusion can be found by subtracting the binding energies of the reactants from the binding energies of the products. How did they get this? I'm totally clueless.

I've got a question on nuclear physics, specifically binding energy. I understand that binding energy is the energy needed to separate a nucleus into its constituents. But something has been bugging me. For example, Two deuterium nuclei fuse together to form a Helium-3 nucleus, with the...

Okay guys, thanks for your input. I forgot that by converting 108km/h gives me 30m/s. I was under the impression that it was 108 x 1000 x 3600, when it should have been (108 x 1000) / 3600 = 30m/s. So by using tan (theta) = v^2 / rg, (theta) = tan^-1 (900 / 100 x 10) = 41.9 ~ 42 degrees...

Question on Motion of a car round a banked track [SOLVED] Homework Statement A racing car of 1000kg moves round a banked track at a constant speed of 108km/h. Assuming the total reaction at the wheel is normal to the track, and the horizontal radius is 100m, calculate the angle of...