Consider the ball is in mid-fall, it hasn't hit the ground yet and has not just been released. There are no external forces because gravity is providing the impulse. Is momentum conservered in this case or not?
I'm not quite sure I understand. If momentum of a system is to be conserved then pfinal = pinitial. Meaning m1v1=m2v2. The masses will cancel meaning the velocities have to equal. But they don't. If the ball doesn't hit the ground and is just falling, where is the momentum supposed to be conserved?
Wow, thank you everyone who has gone through all this trouble to help me. Unfortunately, I feel the situation has gotten a little out of hand. So to prevent people from debating and hitting themselves with baseball bats (ie: zapperz), I'll tell you what my physics teacher explained to me...
Still confused
Thanks for your help but I'm still confused,
So what you are saying is that gravity is causing the centripetal force to exist and that Fc = Fg?
If so then if the gravitational force was doubled then the centripetal force would be doubled as well as velocity? How would I show...
I have a physics lab on centripetal force and I'm stuck on an anaylsis question. The lab requires me to have a piece of string with masses on opposite ends threaded through a tube. The mass at the bottom should hang, while the mass on the top are swung in circular motion. The question asks, if...