Recent content by GabeN

Yeah, I didn't make sense of it until I really thought about gopher's post, than I realized that \frac{1}{ab} Is the same as \frac{1}{ab/1} Which finally drilled into my brain the proper way to solve the equation for a. Such an obvious solution that somehow eluded me...

\frac{1}{ab} • f = \frac{1}{1/a + 1/b} • \frac{1}{ab} = ab = fb + fa = ab - fa= a{(b-f)} =fb =a = \frac{fb}{b-f} I feel like a total dunce. I used the advice given, which should have been obvious to me, and multiplied by 1/ab, which of course gave the correct answer. Thanks for the...

This is where I was getting confused. I'm aware that 3=3/1, I just haven't seen how I could multiply away the denominator of a denominator. Does this look right as the next step, as it seems like the only other logical way I can think of. \frac{1}{ab} • f = \frac{1}{1/a + 1/b} •...

f= \frac{1}{1/a + 1/b} ab * f = \frac{1}{1/a + 1/b} * ab fab = \frac{ab}{b+a} fab{(b+a)} = ab \frac{f(b+a)ab}{ab} = \frac{ab}{ab} = f{(b + a)} = 1 a = \frac{1}{f} - b That's what I came up with. It looks horribly wrong even as I type it, yet, for some I reason...

Ok. This may sound stupid, but I was under the impression one could not just multiply the right hand side(what I assume RHS means). I can get on a computer now and I'm going to try using LaTex.

I described that incorrectly. I meant that I had multiplied the numerators.

Sorry, let me retry that: f=1/[(1/a)+(1/b)]. I hope that makes a little more sense.

Homework Statement Solve the formula f=1/1/a+1/b for a in terms of b and f. The Attempt at a Solution My attempt at this problem was to first multiply all terms by ab, thus getting rid of the fractions in the denominator on the right. I was then left with the equation fab=ab/(b+a)...