Recent content by gake

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    Using torque to find mass of meter stick

    I got it! Thank you! .25mg==25g m==1!
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    Using torque to find mass of meter stick

    Or is it half way?
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    Using torque to find mass of meter stick

    Do they both act from the center of gravity?
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    Using torque to find mass of meter stick

    at 25cm?
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    Using torque to find mass of meter stick

    The 25 cm long part weighs 1\4th of the total and 75 cm weighs 3\4ths, doesn't it?
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    DIffering Weight at equator and poles

    Thank you :)
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    Using torque to find mass of meter stick

    Isn't it 25 cm away, since mass is at 0 and fulcrum at 25 cm? Or is it zero since the portion of the ruler accounted starts right after the fulcrum?
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    DIffering Weight at equator and poles

    gggg3 Intuitively, I wish to say the equator, but I'm not certain why. Is centripetal acceleration greater at the equator, resulting in a weaker normal force? (As far as my question goes)
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    Change in momentum after hitting a wall

    What a dumb mistake! Thanks :)
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    Change in momentum after hitting a wall

    Homework Statement 32) The change in momentum, in kg m/s, that occurs when a 1.0 kg ball traveling at 4.0 m/s strikes a wall and bounces back at 2.0 m/s is A) 2. B) 4. C) 6. D) 8. Answer: C Homework Equations Momentum==Mass*Velocity The Attempt at a Solution I get...
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    DIffering Weight at equator and poles

    Homework Statement 23) A person weighs less at the equator than at the poles. The main reason for this has to do with A) the spin of the Earth. B) the shape of the Earth. C) both the spin of the Earth and the shape of the Earth. D) the influence of the sun, moon, and all the planets...
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    Using torque to find mass of meter stick

    Homework Statement 22) A 1-kg rock is suspended from the tip of a meter stick at the 0- cm mark so that the meter stick balances like a see-saw when the fulcrum is at the 25-cm mark. From this information, what is the mass of the meter stick? A) 1/4 kg B) 1/2 kg C) 3/4 kg D) 1 kg...