I need to find the locations of the singularity of f(z) = Log(2+tan(z)).
So far I have looked at the function in its alternate form
Log(2+tan(z)) = ln(abs(2+tan(z))) + i*Arg(2+tan(z))
If I remember correctly the first part is simple and cannot equal zero.
Now I think the second...
I have been working on showing the equality between
N=0 to ∞ Ʃ cos(2nθ)(-1)^n/(2n)! = cos(cos(θ))cosh(sin(θ))
I started by using the standard series for cosine and putting cos(2nθ) in for the x term.
I did the same for cosh(sin(θ)). I manipulated the forms every way I could think but...