I have been working on showing the equality between(adsbygoogle = window.adsbygoogle || []).push({});

N=0 to ∞ Ʃ cos(2nθ)(-1)^n/(2n)! = cos(cos(θ))cosh(sin(θ))

I started by using the standard series for cosine and putting cos(2nθ) in for the x term.

I did the same for cosh(sin(θ)). I manipulated the forms every way I could think but it never looked anything like the answer I seek.

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# Help with a trig to sum identity.

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