begin by drawing a picture. center the triangle on the xy plane. draw an arbitary inscribed rectangle and label the point where the triangle and rectangle meet as (x,y). you should also have a symmetric point labeled (-x,y). find relationship between y and x (using the length of the 3 sides of...
ok, this is what i got.
AX x AZ = (AB+BX) x (AD+DZ)
= (AB+BX) x AD + (AB+BX) x DZ
= AB x AD + BX x AD + AB x DZ + BX x DZ
AB x AD = (AX+XB) x (AZ+ZD)
= (AX+XB) x AZ + (AX+XB) x ZD
= AX x AZ + XB x AZ + AX x ZD + XB x ZD
and that's...
the prob ask me to prove that if parallelograms ABCD and AXYZ (see the attachment) are such that point X lies on side BC and point D lies on side YZ, the area of the 2 parallelograms are equal.
i need help with solving tihs problem. I'm not really sure how to prove it.
several people started with $300 each, and played a game with the following strange rules. each player pays $10 to the house at the beginning of each round. during each round, one active player is declared the loser...
i euqated that equation and found out that r= + or - 1 so a = + or - 2.
well, that yielded 2 equations. x^10 - 2x + 1 and x^10 + 2x +1. r = 1 is a zeo, but r=-1 is not. what am i doing wrong?
I need some help on how to solve this question. It asks me to find all real numbers a with the property that the polynomial equation x^10 + a*x +1 = 0 has a real solution r such that 1/r is also a solution. I tried plugging in r and 1/r and equating the 2 equations, but that got me nowhere.
I need some help on how to solve this question. It asks me to find all real numbers with the property that the polynomial equation x^10 + a*x +1 = 0 has a real solution r such that 1/r is also a solution. I tried plugging in r and 1/r and equating the 2 equations, but that got me nowhere.