Recent content by ganeshrk

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    Mathematica Mathematica - Analysis of a mass-damper-spring system

    damping ratio = c/(2sqrt(mk)) = 2/(2sqrt(28x13)) = 0.0786 | 7.8% critical damping damped radian freq = unadamped radian freq x sqrt(1 - damping ratio^2) = 0.679 The amplitude of motion of the mass is logarithmically decreasing and it is a function of the damping ratio.
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    MATLAB DSOLVE: Solving 2nd Order ODEs with Initial Conditions

    Homework Statement I am using MATLAB Symbolic Tool Box "Dsolve" to solve 2nd order, linear, ordinary, non-homogenous differential equation with initial conditions. Homework Equations Equation of motion with base excitation (vibration: single degree of freedom system) The Attempt at...
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    Mathematica Mathematica - Analysis of a mass-damper-spring system

    Your mass is 28; spring constant or stiffness is 13. Radian natural frequency is sqrt(k/m) = 0.681 radians/sec or 0.1084 Hertz (cycles/sec).
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