Recent content by garretts16

I think I solved it on my own. Is the new angle 131.4 degrees from the +x ccw?

I don't fully understand the question.

1. 0 2. -748.8 3. 220 4. 628.32

Actually, I found the components of the velocity by mistake.

1. 0 2. -6.5 3. 4 4. 5.46 from what I gathered.

I haven't used the angle yet, I'm not sure how to use it to find the direction after the collision. I set up a momentum equation, and, since it's an elastic collision, I set up a KE equation with it. I had trouble when I ran through the equations: I solved for x in the MV equation, but I got a y...

the x is the velocity in the x direction, and same for y I multiplied each mass times the velocity to get momentum. Then I set that P = MV1 + MV2 and I solved for the missing V. The angle is 140 degrees from 0. Counterclockwise.

Homework Statement A 55kg man is running in the positive y direction at 4 m/s. He is tackled by a 115kg man running 8.5 m/s at a 140 degree angle. What is the speed and direction after the inelastic collision? Homework Equations p=mv p = sqrt of x^2 + y^2 The Attempt at a Solution...

Homework Statement A 2kg block is resting on a frictionless table. It is hit, head on, by a 1kg block heading at 4 m/s. The larger block is sitting 3m from the edge of a 5m long table. The collision happens with the smaller block's distance being 2m from the table and the larger blocks d =...