Theoretically could you solve the question if you knew the measurements of how much sodium bicarbonate had fallen in right? I'm guessing since this is an assignment I can probably just model a realistic scenario and apply suitable values? Is there a way to solve the question if you knew the...
Thanks for responding Borek and Tiny Tim!
I believe my brother was allowed to choose and he has chosen sodium carbonate Na2CO3. How should I start considering this problem? Would it just be trichlorocyanuric acid + Na2CO3 <--> ? and then find a Ka value of cyanuric acid?
Sorry for not...
Homework Statement
A swimming pool with 95000L of water with a pH of 8.9 needs to be lowered to a more suitable pH using an acidic substance. An ideal pH would be within the range of 7.2-7.6, so let's just assume that the pH we're hoping to achieve is 7.4. My brother chose...
Terribly sorry, I have worked this out. Just found the relationship between Gibbs Free and the equilibrium constant, rather than the reaction quotient.
Sorry!
THe answer is 1.1*10^3
Homework Statement
The standard reduction potentials for Ni2+ and Sn2+ are as follows:
Ni2+ + 2e− → Ni E° = −0.23 V
Sn2+ + 2e− → Sn E° = −0.14 V
Calculate the equilibrium constant at 25°C for the reaction Sn2+(aq) + Ni(s)→ Sn(s) + Ni2+(aq)
Homework Equations
Nernst...
[HClO] + [ClO-] = 0.39M
So if you were to do log(acid / base), it would simply be 0.39 since all the sums of the acid must be equal to the original concentration? hence the answer is just 0.39 + 3.932?
Hey Borek,
thanks for the sites, but I"m a little confused. Chembuddy says "the sum of concentrations of all acid forms present in the solution must be identical to the concentration of acid added."
Does that mean for the log(acid/base), the acid value would be the Ka and the base just the Kb?
Homework Statement
Determine the pH when 0.39 mol HOCl is added to sufficient water to make 1.000 L of solution. (Ka (HOCl) = 3.700 x 10-8)
Homework Equations
Ka = Kw/Kb
pH = -log(pKa) + log(acid/base)
The Attempt at a Solution
For this question first we need the concentration...