Recent content by Gauranga

Thanks...

Guys can you please just check the method i applied for torque calculation. First of all i found the moment of inertia.Then i have the value of a stroke, from where i calculated the rpm. Then by the formula 2.pi.rpm/60 ,i got the angular acceleration in rad/sec.So i devided the...

I am all into it and it is the part of my last question which is proceeding further and further as i have lots to do about it.However thank.

First of all i changed the rpm 3.6n into rad by the formula omega=2*pi*3.6/60. And then i divided the time with it to get the angular acceleration.

i think i have found it out by founding angular accn 0.75 rad/sec^2 and by the general formula torque = moment of inertia * angular accelaration.The result is 5.39 kgm^2 rad/sec^2 where i think the rad is not the mater.So the unit seems good.But i was not sure.can someone say that the method...

So i have the uniform accelaration.My rpm is 3.6,acceleration time is half second and my moment of inertia is 71502884 gm cm^2 and in case i have the mass also 75.8 kg.Can somebody help me to use these values to find the torque.

why are you using the formula 1/3ml^2 inspite of 1/6ml^2?Then why have u taken the a as 4a/2.Please explain and if u got the right answer,please explain it here.

(1/3)*M*(l^2), where l is 4a/2=2a, isn't the l here is 32a^2

Hehehhe thanks a lot for the information.I was looking for something more than that.So that i can find the torque from above information but i understood that i need the acceleration time which i have to get.Thanks by the way.

Hey guys as i found out the moment of inertia and the center of mass of the machine, now the problem is to find our the torque.So i have 300rpm and I = 180000 gm*mm^2. but i can't relate between these two quantity to find out the torque.can somebody provide me some relationship.Is it so that...

Hey.I am learning the solid edge and i didn't know that i can find out the moment of inertia in that.However thanks a lot.

I think i will calculate the moment of inertia by the formula of a hollow torus and then divide it to 8 as the angle between the two radius connecting the arc is 45 degree.but for this i have to take a assumption that this body is a homgeneous torus because there are some slots and additional...

I am an engineer doing and i know the basic equation but the problem is with the part.Basically it is an arm of an instrument which moves and i have to calculate the moment of inertia of it . But the form of it is a little complex. It is a hollow section of solid steel which is similar to a...

Guys i need a little help in finding the moment of inertia of a part of a machine which looks like the part of a torus as the arc of a circle.Can somebody help me out with it please?