Recent content by gavhowe

thank you

Ok I have had another look at the problem and tried is a different way, please could some let me know if this is correct: 981N*0.74m*Sin16 = ? * 0.215m*Sin62 (981N*0.74m*Sin16) / (0.215m*Sin62) = 1054N

yes the arm is free to rotate around the pivot at the base of it. The ram will slightly change the angle of the arm when it moves in and out. My calculation were, to first calculate the torque at the pivot: 100kg x 9.81 x 0.147m = 203.07 Nm so 203.07 / .06m = 3384.5N to support at the...

Hello, I am after a little help on an applicaition, I need to calculate the force require to hold a pivoted arm in a position using a pneumatic ram. Basically the arms C of G is 740mm up the arm, and the arm weights 100kg. Roughly 1000N working at an offset of 147mm. The arm is 16 degrees...