Recent content by Gee Wiz

∫xy^2(\hat{z})dxdy I kind of had this before. I then was thinking along the lines well okay for when I did electric flux if I had a electric field E and I needed to find the charge enclosed and I was given a charge density I would start: E*2*π*r^2=ρ*π*r^2/εo then things would cancel and I...

Homework Statement Let J=xy^2(\hat{x}+\hat{y}+\hat{z}) A/m^2 denote the electrical current density filed -i.e, current flux per unit area - in a region of space represented in Cartesian coordinates. A current density of J=xy^2(\hat{x}+\hat{y}+\hat{z}) A/m^2 implies the flow of electrical...

Ahh, I see my mistake. I was using from units for the volume. Thank you! I got the correct answer now. I appreciate everyone's help

I get .117

Here is everything I am doing =(5/2)*(1.381e-23)*(32.23)*( (1*.0042)/(.08206*293) )* (6.022e23)

It's smart physics

I am not 100% sure about your units for P and V (it may just be notation i am not familiar with) I usually see [P]=atm or pascals, [V]=L (m^3=mL)

I get the same message with that answer that I do with my previous one. "It appears you have made a power of ten error"

I believe so

1.74e-4

right, and I think that m^3=mL=.001L

yes i think so

Yes. I did 1*.0042e-3/(.08206*293)..converting the kPa's to atms and Celsius to k

n= 1.746e-7 N=1.05e17

it is the degrees of freedom (5/2 for diatomic)*(Temperature)*(K which is a constant 1.381e-23)*(# of molecules)