Recent content by geezer73

Thanks much. I have some 3D graphing software, so I'll spend some more time with it. It's just good to know that the integral was not as simple as a 2D area. I was losing some marbles trying to reconcile 8/3 with pi :-)

Thanks, but I'm still trying to visualize. It sounds like, if this value is a volume, its average height on the z axis would be about .85. Is this in the right ballpark?

So this involves the z axis?

Can this be graphed in 2 dimensions?

Thanks for the quick reply. I'm still unable to visualize what the "area under y" looks like. What would it's graph be?

I'm in the middle of the Great Courses Multivariable Calculus course. A double integral example involves a quarter circle, in the first quadrant, of radius 2. In Cartesian coordinates, the integrand is y dx dy and the outer integral goes from 0 to 2 and the inner from 0 to sqrt(4-y^2). In...