Recent content by Gemini_Cricket

Okay I'll try to make it short. There's a microwave transmitter, it transmits microwave radiation onto a foam cube of steel chrome balls that act as scattering centers. There is a receiver on the other side that picks up the radiation after it is reflected. The turntable that the cube sits on...

Homework Statement I wasn't sure where to post this question. I hope I picked the right section of the forums. This is from intermediate lab. The lab is for Bragg diffraction using microwaves. The grazing angle is a measured quantity along with the voltage (which was measured using an...

Ah okay. I had thought it might have something to do with the complex conjugate. So for the complex conjugate you just get... e^(-λ|x|)*e^(-λ|x|) = e^(-2λ|x|)

Homework Statement ψ(x,t) = Ae^(-λ|x|)e^(-iωt) This is a rather long problem so I won't get into the details. I understand how to normalize, and most of the rest of the problem. I also have the solutions manual. I just need an explanation of why this goes to Ae^(-2λ|x|). I can't figure it...

Yeah I just learned a hard lesson to not pay attention to the equations in the book, because they need to be somewhat "derived" for each problem. Thanks for all the help. Its kind of funny, I had this as my first answer. Yet I erased it in lieu of my friend having a seemingly better explanation...

okay so it should be gamma used as a multiplier instead of a divisor. I get L'={gamma}v{delta}t. I hope that's right because it makes sense to me after rereading this post.

Why would ship 2 be shorter in ship 2's frame? I thought moving objects appeared smaller. Wouldn't 2 be stationary to 2, but moving relative to 1? And therefore, 2 would be larger to 2 than to 1. Also, 1 would appear smaller to 2? I am probably looking at this way wrong... I appreciate your...

No, I am asked to find Ship 2 in Ship 2's frame. Well I worked it out equating the velocities. It's just L' = L/γ though. I need it in terms of Δt, and I don't believe the previous step, L' = LΔt'/Δt, counts does it? That's in terms of both times...

I am very confused here. You say that L is the length of ship 2 in ship 1's frame. Wouldn't that just make the answer to the problem L = vΔt?

Moving lengths are smaller. In ship 1's frame, ship 2 is moving, so L should be smaller than L'.

Ship 2 in it's own frame should be a length of L' = vΔt'. Here's what I've come up with. Using instead Δt=γΔt' and the above equation. I get L'=vΔt/γ.

Homework Statement Spaceship 1 passes spaceship 2 with a relative speed v. An observer in spaceship 1 measures a time interval ∆t for spaceship 2 to pass by. Find the length of spaceship 2 as measured in its own rest frame, i.e., find the proper length of spaceship 2 in terms of ∆t...