Recent content by Genza

Quick question on an old thread, how do Wooh and ahrkron know that the radius tangent to the longer side will split the side into segments of 5 and 2?

I figured out that the density (p) is just 1 (because it's a water squirter) and the gauge pressure at the nozzle (P2) is 0. And the pgy terms are also 0 because the squirter is just horizontal. So using equation 2 from above (bernoulli's eqn) I got: P1 + 1/2(1)(V1^2) + 0 = 0 + 1/2(1)(V2^2) +...

Homework Statement Area at the end with the plunger (A1) = 8cm^2 Area at the nozzle (A2) = 0.5cm^2 Velocity at the nozzle (V2) = 2m/s What is the force being applied to the plunger? Homework Equations A1*V1=A2*V2 P + (1/2)pV^2 + pgy = P + (1/2)pV^2 + pgy P=F/A The Attempt at...