Alright, this is what I've got for part 2)
If I let abv(x-y)<\frac{a}{N}, then I can say that abv(Nx-Ny)<a, meaning abv(Nx-Ny)\in[-a,a].
Now if I let abv(F(x)-F(y))<\frac{m}{N}, I can say that abv(NF(x)-NF(y))<m because of part one of the proof. Since \frac{m}{N}<\epsilon, I can then say...