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Graduate Finite field is algebraically closed under constraint?
A field K is called algebraically closed field if any no-zero polynomial has at least one root in K. Given finite field F_q, q=p^m, p is a prime and m is non-negative integer. A famous property of finite field is any element in F_q satisfies: x^q=x. Then I have such an assumption...- gepolv
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- Closed Constraint Field Finite
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- Forum: Linear and Abstract Algebra