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gepolv
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A field K is called algebraically closed field if any no-zero polynomial has at least one root in K.
Given finite field F_q, q=p^m, p is a prime and m is non-negative integer. A famous property of finite field is any element in F_q satisfies: x^q=x.
Then I have such an assumption:
F_q[x_1,x_2,...x_n] has at least one root with the constraint "degrees less than q".
I have two questions:
1: Is this assumption true?
2: If it is true, can I say "F_q" is algebraically closed under condition "degrees less than q"?
Thanks a lot.
Gepo
Given finite field F_q, q=p^m, p is a prime and m is non-negative integer. A famous property of finite field is any element in F_q satisfies: x^q=x.
Then I have such an assumption:
F_q[x_1,x_2,...x_n] has at least one root with the constraint "degrees less than q".
I have two questions:
1: Is this assumption true?
2: If it is true, can I say "F_q" is algebraically closed under condition "degrees less than q"?
Thanks a lot.
Gepo
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