Recent content by gimpycpu

I think that I found it, you can reduce the big squareroot of death to a mere \sqrt{1+\frac{-1}{-∞}} = 1 so the final equation is equal to \int_{-1}^{1} 2\pi\sqrt\frac{x^2 (1 - x^2)}{8} * 1 dx = 2\pi\int_{-1}^{1} \sqrt\frac{x^2 (1 - x^2)}{8}dx which is a lot simplier to integrate

Hehe I know right the original function is \sqrt{ \frac{x^2 (1 - x^2)}{8}} so I have to do the surface of revolution formula on this which is defined S = \int_a^b2\pi f(x)\sqrt{1+(\frac{dy}{dx})^2}dx

Greeting everyone I am trying in integrate this function, to obtain the surface of revolution of a function. 1. Relevant equations \int_{-1}^{1} 2\pi\sqrt\frac{x^2 (1 - x^2)}{8}\sqrt{1+(\left| x\right | \frac{-2x^2+1}{2(-x^2+1)^{1/2}*2^{1/2}x}})^2 2. The attempt at a solution I tried to...

Thank you for your help I had no idea how to type correctly on the forum

no I can't use the kinect equation, but i found the answer with calculus f(0) = 32 so speed = f(x) = -9.8x + 32 so if I integrate this from 0 to 32/9.8 it gives me 52.24 meters (-9.8t^2)/2 + 32x (-9.8(32/9.8)^2)/2 + 32(32/9.8) = 52.24 meters which is a mere approximate

Homework Statement A ball is thrown at 32m/s vertically what is the max height the ball can attain. Homework Equations no equation is given except initial speed The Attempt at a Solution so my guess is since the gravity is 9.8m/s^2 if I integrate 9.8m/s^2 = 32 it gives me 2.1396...