Recent content by glitchy

yep, closed

Any help is greatly appreciated, A 3-liter vessel contains 2kg of water, 0.05kmol of steam, and 15cm3 of ice (density = 990kg/m3). If the vessel is heated until its entire contents have vaporized, what is the density of the vapor? now i know I've to use M(in) - M(out) = M(vessel). If...

Hey all, got a few questions i need help at. any hlep is fully appreciated. A rigid sealed 50-liter tank contains argon at a pressure of 5MPa and 400K. 1. What is the mass of argon - what i did here was use PV=mRT, so that means (5000kPa)(50)=m(value from table)(400). what I'm slightly...

Hey, I got a final coming up and I need to check this question since it's been killing me. I got an answer of 4.5 rad/s Any one mind verifying for me. any help is appreciated thank you

i'm sorry, ur losing me a bit here. how can u differentiate with respect to time if you don't have a 't' in the whole thing. it's basically a constact.

i understood everything u said clearly apart from " then i differentiated with respect to time and put in 10 for ds_b/dt "

eok20: you mind showin me you workin. I'm assumin you got the same for the 'i' component though?

Hey all, anyone help me verify the answer for the question i got Va=-5(root 3)i + 3j ft/s and Aa=45i-29j ft/s^2

done, then

I'm really getting stuck at this and I'm trying to read on it but it's confusing. I need just a start-up for this equation which is to be solved with the method of frobenius. 3xy" - 4y' - xy = 0 Just need a start. Any help is appreciated. Thank you

A closed rectangular bos with a volume of 16cu. ft is made from 2 kinds of materials. the top and bottom are made of material costing 10cents per square foot and the sides of the material costing 5censts per sqaure foot. what r the dimenstions of the box so that the cost of the materials is...

so far i got W = 125 W1 = 5csc5x W2 = -5cos5xsin5x=-5(cos5x)^2 . tan5x W3 =-5 therefor U'1 = csc5x/25 U'2 = -cos5xsin5x/25 U'3 = -1/25 y=C1 + C2cos5x + C3sin5x + (1/5)Intan(5x/2) + (1/250)(cos5x)^3 - (1/25)xsin5x i got that answer. can anyone verify that for me.

y''' + 25y' = csc(5x) i got the y (complimentary) = C1 + C2cos5x + C3sin5x. I'm just having minor difficulties getting the y (particular).

Hey all how u doin. i need help with the following 2 questions. 1. A mass m is given an initial velocity of 'u' in the x-direction. It moves in a medium that resists its motion with a force proportional to the velocity, F = -kv. Find v(x) and how far the far the mass travels before stopping...

You have to come up with the dfq.