Alright -- the final equation i get is 6e^x + 2x^3 - 3x^2 - 3xe^x = 0
The 2 answers that the book gives work in this equation...but how the hell would I solve this?
If I were to set 6e^x + 2x^3 - 3x^2 - 3xe^x equal to y in my calculator and graph it, is there a way for the calculator to tell...
Here is what the question asks:
Find the coordinate of all points in the graph of y=3e^x - x^3 at which the tangent line passes through the point (1,0).
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I am told that the 2 points are (-.872, -1.027) and (2.275, 13.657). Any help at all that you can give...