Recent content by godkills

For energy conservation does it apply to both conservative and non conservative forces?

Yup that's what I did. I should really start explaining what happens in the problems before solving problems. Anyway, Thanks a lot!

Yes, It turned out I was a little confused with the pictures. I have another question that was stated above your post.

Oh another question why do i have to subtract orange momentum from apples? I mean if there is no initial momentum before the colllision shouldn't initial momentum is equal to the final? which would mean something in this form 0 + 0 = 0 + 0? so that it is plus? instead of minus?

Oh sorry, What I meant was no initial momentum. When you do momentum for y direction. Such that the equation would be 0 = final momentum. I have the problem if you want me to type it. Astronauts on opposite ends of a spaceship are comparing lunches. One has an apple, the other has an...

Can someone tell me why there is no initial momentum when these 2 objects collide in the y direction? At first these objects were going in the x direction this picture shows what happens when the objects collided. Apple Orange =======> <========...

Ah nvm, i found out the method was wrong and so I had to use this one. http://upload.wikimedia.org/math/a/b/6/ab6645eaf09c6da1ba47b0f662615140.png

The two masses in the Atwood's machine shown in Figure 8-23 areinitially at rest at the same height. After they are released, thelarge mass, m2, falls through a heighth and hits the floor, and the small mass,m1, rises through a height h. (a) Find the speed of the masses just beforem2 lands...

s2=21.51 s1=6.56 new ones still wrong i seriously don't know why i performed the calculations correctly

1790kg x 16 m/s = 1790s1 + 750 s2 where s1 and s2 is velocity of truck and car after collision. s1=(28640 -750s2)/1790 1/2(1790)(16)^2=1/2(1790)(s1)^2 +1/2(750)(s2)^2 196=s1^2+0.42s2^2 equation number 2 then i plugged in s1 into equation number 2

A 750- kg car stopped at an intersection is rear-ended by a 1790- kg truck moving with a speed of 16.0 m/s If the car was in neutral and its brakes were off, so that the collision is approximately elastic, find the final speed of the truck. Find the final speed of the car. 256 =...

yes i had the FBD drawn and i understand i think how the larger mass should be moving the the left due to it's heavy weight but i am not getting why for the second mass tension is subtracted from the weight. i drew a triangle perpendicular to the larger mass. indicating sin(35)mg is positive.

Two blocks are connected by a string-one on an incline, the rope draped over a pulley, and one hanging from the string. The smooth inclined surface makes an angle of 35 with the horizontal, and the block on the incline has a mass of 5.7 kg. The mass of the hanging block is 3.2kg. Find the...

Your friend's 12.4 g graduation tassel hangs on a string from his rearview mirror. (a) When he accelerates from a stoplight, the tassel deflects backward toward the rear of the car. Explain. (b) If the tassel hangs at an angle of 6.44 degrees relative to the vertical, what is the acceleration of...

okay i just figured out myself question states how fast is it being pulled meaning the x component when it is being pulled so you find the force of the x component which is cos(x) multiplying the force of the hypotneuse which equals to the force of x component Now F = ma Force/mass =...