Okay, I just looked at it and you don't have to solve for velocity. I changed L=r*m*v to solve for v and substituted v in the equation of F = mv^2/r. I set that equal to kqq/r^2 and then I eventually set everything equal to L first, then solved for r. my final equation was, L^2 = k*q*q*r*m...
Ah. I'm still confused. So do you have to solve for the velocity first and substitute F for mv^2/r? So the end equation would be, mv^2/r = k q1q2/r^2? And with the charges, would q1 be the charge of the electron and q2 would be the charge of 2 protons?
Homework Statement
A positively charged Helium atom has two protons in the nucleus and one electron in the shell, in a classic model of the atom, this electron is in a circular orbit around the nucleus with an angular momentum of 4.718x10^-34 Js. What is the radius of the orbit?Homework...