Hi,
I am really confused with circle theorems, attached is a diagram and I need to find out ABC and CBO.
I have worked out that angle ACB is x degrees, and also know that angle OAC is equal to angle OBC.
But I don't know how to work out the what either are
Thanks
Graham
I don't, I understand that the strong has to balance the vertical and horizontal force, but can't work out how the horizontal AND vertical forces are balanced at the point of string.
Thanks again
Graham
The point is we don't know if it is string, presumably they would have mentioned it was string if it was important. But anyway.
The force applied to the two balls must be the same to both of them as the balls are not moving and is the same string. Do you mean by reducing the the length of the...
"In the text you read that electrons are removed from atoms by rubbing. An electron needs energy to remove it from an atom. Explain, using scientific terms how rubbing provides this energy"
Do I just need to say that by rubbing you are changing the charge because of the movement of protons to...
There are two balls which are apart from each other but there is a line going from the balls diagonally up and these two join. The topic is electricity so I have said the two balls have like charges as they are repelling.
See [PLAIN]www.kgmm.co.uk/balls.GIF[/URL] for diagram.
The question...
I just knew I'd be back:
A field gun of mass 1000kg, which is free to move, fires a shell of mass 10 kg at a speed of 200 m/s.
(b) What is the momentum if the gun just after firing? - Do we use momentum = mass X velocity, and if so what is the velocity it moving back and if so how is that...
Sorry I meant 2kg, a typo there. I also mistyped the x on the RHS top line, they should have been +.
Thanks for all your help, I do not have my exercise book so couldn;t remember the equation for it. In case your wondering I'm an english pupil in year 10 which makes me 15 yrs old, so...
With that in mind is the following right:
(m1 X u1) + (m2 X u2) = (m1 X v1) + (m2 X v2)
(3*3) + (2*2) = (3*v1)+(2*v2)
13 = (m1+m3) * v (is that the right letter to use?)
13 = 5 * v
v = 13/5
v = 2.6
Is that right, and if not where do you mind explaining where I went wrong please...
Thanks for that. One more question what is V1 and v2 final velocity which is presumably 0?
Or do I have to sub in the values and work them out?
Thanks for your help, it's greatly appreciated
Graham