You're awesome! Makes so much sense now.
(-√6i)(-√14i) would be (√84i^2) correct? Then the i^2 would make it -√84? Just want to make sure I fully understand this.
:mad: I really hate these problems.
(2+√7)/(3-√-11). What the heck?
I start out by multiplying both sides with the conjugate again. This is where I am stuck lol. Can someone tell me what I am doing wrong while multiplying the conjugate?
(3 - √-11) is the same as 3 - √11i correct? So I...
I redid this problem and cannot find anything wrong.
It's just that i have this gut feeling that this answer is wrong for some reason. Way longer than any of my past answers for other problems like this. If it's right though then I guess there's nothing I can do to simplify that!
I redid the problem like 2 times again but cannot catch on to my mistake. My mistake is in the denominator correct?
(2√2 - √7)(2√2 +√7)
I'm going to take this step by step.
(2√2)(2√2) = 4√4 = 8
(2√2)(√7) = 2√14
(-√7)(2√2) = -2√14
(-√7)(√7) = -√49 = -7
2√14 - 2√14 cancel each other out.
I have some problems I am stuck on. The goal here is to simplify radicals in the denominator. I understand that when there is a binomial in the denominator, you need to multiply both sides by the conjugate. For some reason though, I seem to be having trouble doing that or am making a mistake...