Recent content by GreenLantern674

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    Power in an RL Circuit

    Okay, I found the formula IE=RI^2+IL(dI/dt) and I used that to solve (b), which turned out to be 19 W, but that formula didn't work when I tried it on (c). I think what I have to do is find the total power in the system and subtract my answer from (b) from that. But I'm not sure. Any suggestions?
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    Power in an RL Circuit

    An RL circuit in which L = 9.00 H and R = 5.00 is connected to a 24.0 V battery at t = 0. (a) What energy is stored in the inductor when the current is 0.500 A? (b) At what rate is energy being stored in the inductor when I = 1.00 A? (c) What power is being delivered to the circuit by the...
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    Inductance RL Circuit

    Never mind. I got it.
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    Inductance RL Circuit

    Okay, so what you said got me thinking, and I remembered that the time constant equals 1/t and that equals L/R so I set 1/1.4 = L/0.3 but that didn't work. Am I on the right track? P.S. is inductance negative?
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    Inductance RL Circuit

    [SOLVED] Inductance RL Circuit Calculate the inductance in an RL circuit in which R = 0.300 and the current increases to one fourth its final value in 1.40 s. I tried doing this with V=IR, (I know, the easy way didn't work). I also tried I= V/R(1-e^(Rt/L)) but I don't know what V would...
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    Square Wire Magnetic field

    Also, I know that the direction of the magnetic field is to the left of the page.
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    Square Wire Magnetic field

    Can anyone help me with this problem? In Figure P22.31, the current in the long, straight wire is I1 = 8.00 A and the wire lies in the plane of the rectangular loop, which carries 10.0 A. The dimensions are c = 0.100 m, a = 0.150 m, and = 0.350 m. Find the magnitude and direction of the net...
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    Gauss's Law Sphere Problem

    Yes, but the electric field in the cavity isn't zero. That's what initially confused me.
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    Gauss's Law Sphere Problem

    A sphere of radius 2a is made of nonconducting material that has a uniform volume charge density . (Assume that the material does not affect the electric field.) A spherical cavity of radius a is now removed from the sphere, as shown in Figure P19.62. Show that the electric field within the...
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    Oscillating Slingshot

    Also, the problem defines L as the horizontal aspect of the triangle. Can I use the small angle theorum to assume that the hypotenuse is the same as the horizontal component?
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    Oscillating Slingshot

    I know that max acceleration equals Aw^2 and we've used the formula a=Aw^2 cos(wt+phi)
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    Oscillating Slingshot

    I've never seen that kind of equation before, except in the equation A=[F/m]/(sqrt(w2 - (k/m)2) , which turns into something kinda similar when you solve for w. Also, what is the "d" in md^y/dt^2 = -2Ty/L?
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    Oscillating Slingshot

    A ball of mass m is connected to two rubber bands of length, L, each under tension T, as in Figure P12.49. The ball is displaced by a small distance y perpendicular to the length of the rubber bands. (a) Assuming that the tension does not change, show that the restoring force is -2yT/L ...
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    Dampened Oscillations Problem

    Never mind. It turns out I was using the wrong formula.
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