How do you calculate inductance in an RL circuit?

AI Thread Summary
To calculate the inductance in an RL circuit with a resistance of 0.300 ohms and a current increasing to one fourth of its final value in 1.40 seconds, the user initially struggled with the equations V=IR and I= V/R(1-e^(Rt/L)). It was clarified that the voltage (V) can be treated as a variable, allowing for the use of ratios in the time constant equation. The user attempted to relate the time constant to inductance using the formula 1/t = L/R but found it unhelpful. Ultimately, the user resolved their confusion about the inductance calculation.
GreenLantern674
Messages
27
Reaction score
0
[SOLVED] Inductance RL Circuit

Calculate the inductance in an RL circuit in which R = 0.300 and the current increases to one fourth its final value in 1.40 s.

I tried doing this with V=IR, (I know, the easy way didn't work).
I also tried I= V/R(1-e^(Rt/L)) but I don't know what V would be in this equation. Can someone help me out here?
 
Physics news on Phys.org
GreenLantern674 said:
Calculate the inductance in an RL circuit in which R = 0.300 and the current increases to one fourth its final value in 1.40 s.

I tried doing this with V=IR, (I know, the easy way didn't work).
I also tried I= V/R(1-e^(Rt/L)) but I don't know what V would be in this equation. Can someone help me out here?

The value of V itself will not matter -- you are dealing with ratios and the time constant equation that you show. Just leave it as a variable "V", and see if you can solve for the inductance...
 
Okay, so what you said got me thinking, and I remembered that the time constant equals 1/t and that equals L/R so I set 1/1.4 = L/0.3 but that didn't work. Am I on the right track?
P.S. is inductance negative?
 
Never mind. I got it.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
1
Views
750
Replies
5
Views
2K
Replies
3
Views
1K
Replies
18
Views
2K
Replies
6
Views
2K
Replies
6
Views
3K
Back
Top