How do you calculate inductance in an RL circuit?

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Homework Help Overview

The discussion revolves around calculating the inductance in an RL circuit, where resistance is given as 0.300 ohms and the current reaches one fourth of its final value in a specified time of 1.40 seconds.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore various equations related to voltage and current in RL circuits, questioning the role of the voltage variable in their calculations. There is also a consideration of the time constant and its relationship to inductance and resistance.

Discussion Status

Some participants have provided guidance on focusing on the ratios involved in the equations rather than specific values. There is an ongoing exploration of the relationships between the variables, though one participant expresses uncertainty about their approach.

Contextual Notes

One participant questions whether inductance can be negative, indicating a potential misunderstanding of the concept or the parameters involved in the problem.

GreenLantern674
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[SOLVED] Inductance RL Circuit

Calculate the inductance in an RL circuit in which R = 0.300 and the current increases to one fourth its final value in 1.40 s.

I tried doing this with V=IR, (I know, the easy way didn't work).
I also tried I= V/R(1-e^(Rt/L)) but I don't know what V would be in this equation. Can someone help me out here?
 
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GreenLantern674 said:
Calculate the inductance in an RL circuit in which R = 0.300 and the current increases to one fourth its final value in 1.40 s.

I tried doing this with V=IR, (I know, the easy way didn't work).
I also tried I= V/R(1-e^(Rt/L)) but I don't know what V would be in this equation. Can someone help me out here?

The value of V itself will not matter -- you are dealing with ratios and the time constant equation that you show. Just leave it as a variable "V", and see if you can solve for the inductance...
 
Okay, so what you said got me thinking, and I remembered that the time constant equals 1/t and that equals L/R so I set 1/1.4 = L/0.3 but that didn't work. Am I on the right track?
P.S. is inductance negative?
 
Never mind. I got it.
 

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