Recent content by GRice40

I don't know how to solve the problem, but Pexp(-kx) would probably mean P^(-kX). (P raised to the negative kx). K should be some kind of constant, while x is most likely the distance between the objects, or some other form of variable distance. Sorry I can't help more, but that should at...

Appreciate the help a lot, bud! I'll probably be on here tomorrow with another question, so keep an eye open ;)

Alright, that's fantastic. To be honest, I see what the real problem was. In the equation sheet I was given for the exam, it has Q = nC(dT), not Q = nCv(dT). If I had known it was Cv instead of some other C that I didn't really know, this would have been MUCH simpler! Thanks for all the help...

Alright, maybe I'm slow, maybe it's late so I'm not thinking real well, but I am still just as stuck. Trying to solve it symbolically sent me down a long rabbit run of equations...I'll try and clean them up for you, but there's a lot to fix, I'm sure. Ok, dU = Q - W = Q - (-800) also...

Ok, I suppose the biggest thing I'm wondering (most of those calculations were desperate attempts to find something =P) is about the "n". Because the number of moles of gas stays the same, can we assume that there is one mole of gas? Or maybe not that there is one mole, but that n remains one...

Howdy all, I have a final coming up, and I'm having a very difficult time grasping a few concepts about the ideal gas laws, specifically a problem with isobaric compression. Homework Statement Alright, the intro to the problem is: A quantity of ideal gas is slowly compressed to 1/3 of...

I still don't know where to go from there, it seems like I need another variable somehow...

One rotation is 2(pi) radians, iirc.

Homework Statement An Earth satellite moves in a circular orbit with an orbital speed of 6200 m/s. Find the time of one rotation as well as the radial acceleration of the satellite in orbit. Homework Equations Ac= V^2/R mAc=mg V= 2(pi)R/t The Attempt at a Solution Ok, I've...

Ok here's what I got: F(out) = m*a1 = Tsin(30) W = M*a2 = Tcos(30) So if you divide the two you get: (m*a1/m*a2) = Tsin(30)/Tcos(30) which reduces to (a1/a2) = sin(30)/cos(30) or (a1/9.8) = .577 .577(9.8) = a1 = 5.66 m/s^2 So 5.66 = 4(pi)^2R/t^2, 5.66 = 217.13/t^2 t^2 =...

The centripetal force should be Tsin(30), I think?

I assume that because she is staying in place in the y direction, that the y direction is in equilibrium. So here's what I have: Tcos(30) = m * (9.8) (Another possibility that is coming to mind is: Force(out) + W = T) (Here's the other possibility running through my mind: Force(out)...

Hmm, gravity pulling them down would be my guess?

Hope this works, we'll see!

Here's what I have so far: Radius: 3 + 5sin(30) = 5.5 m V = d/t = 34.56/t Circumference = 2(pi)(5.5)= 34.56 Acceleration = V^2/R = (34.56/t)^2/5.5 That's about as far as I can get without another variable that I know =/