I got an offer to do Physics and nanotechnology from Hull (one of the only 4 places that do the course i want to do) and i wanted to know what people think of the physics department there. I'm not going to get three A's and get into birmingham currently the grades I'm aiming for are BCC in IT...
I'm doing A2 Edexcel maths and i keep on forgetting the trig functions so can someone take a look and tell me if I've got it right.
So far:
Sin^2(x)=cos^2(x)=1
so:
sin^2(x)=1-cos^2(x)
cos^2(x)=1-sin^2(x)
this is where i get abit stuck
(sin^2(x)+cos^2(x)=1)/cos^2(x) =...
Sorry sorry sorry sorry sorry to waste peoples time, me and my teacher had a look at it today and ,my answer is right but there is a huge error because of the rubbishy equipment i was stuck using
I made a force extension graph and the gradient is k i use that in the formula E=kL/A
where L is the original length and A is the cross sectional area of the wire.
Homework Statement
I'm supposed to calculate the youngs modulus of a 2 meter length of copper wire.
Homework Equations
None
The Attempt at a Solution
for 30SWG i get 26GPa
for 38 i get 3.1 GPa
and for 24 i get 49 GPa
Youngs modulus of copper is meant to be ~100GPa (from wiki)...
I did some working on it today and i think you're right, I'm using Newtons, millimetres and metres in the same equation, i converted all the units properly and I've got a more sensible answer now.
Sorry.
I've got to work out the Youngs modulus of a meterial using the equation k=EA/L which rearrnged to E=kL/A i know k because its the gradient of a force extension graph i made, A is the x-sectional area of the wire and L is original length of the wire. wiki says the youngs modulus of...
[SOLVED] More hookes law question
Homework Statement
i can't get the equation to work out to the right answer of 110-130Gpa
Homework Equations
E=kL/A
k-1.45
L=2metres
A = 0.292cm
The Attempt at a Solution
i get 0.0099Gpa
i think I've figured out how you get to that
E=FL/Ae
EA=FL/e
EAe=FL
EAe/L=F
F=ACe (if C equals youngs mod/length)
Which rearranges to e=F/A/C
i think that's right... i hope
scratch that i can also get the equation k=EL/A but now I'm totally stuck
i could substitute that k into the f=ke equation but I've been told that the youngs modulus was for a unit length so i would have to do something to...
by substituting i can get E=kl/A
A is going to be known because i'd know the wire gauge and using rho=f/a i can work out the force but i still can figure out how i'd find k unless i'd already know it when working out
Am i getting close?