Thanks. Yea it was simple. I had just gotten so used to putting my answers in terms of variables, I didnt notice that they had asked for a numerical value. : )
Alright I figured out what I was doing wrong for parts B, C, and D. I got (1/2)*(Z/(4piepsilon0))*e^2/r for B), -((Z/(4piepsilon0))*e^2/r) for C) and -(1/2)*(Z/(4piepsilon0))*e^2/((N^2(hbar^2/((1/(4piepsilon0))e^2m)))/Z) for D).
I would just like some guidance now on this last part.
(e)...
Like I said before, to find the mass you don't need to use the mass and radius of the earth. The gravitational force on the surface of the Earth is 9.8 N/Kg. So take 600N/(9.8N/Kg) and it will give the mass of the person.
I agree with your answers to 1 and 2. but for the rest,
3 is true based on the principles of elastic collisions and conservation of momentum
4 is false if mechanical energy is referring to kinetic energy since energy is lost
5 is true - its just a basic principle of vectors
6 I am not too sure...
You have the equation for force exerted by the planet.
F = (G x M x m)/(R2)
You know G (a constant), M (1/100 the mass of the earth), and R (1/4 the radius of the earth).
All you need is the mass of the person. If the Earth exerts 600N on this person, then his mass is equal to 600N/(9.8N/Kg)...
Homework Statement
The Bohr model
The Bohr model correctly predicts the main energy levels not only for atomic hydrogen but also for other "one-electron" atoms where all but one of the atomic electrons has been moved, as as in He+ (one electron removed) or Li++ (two electrons removed). To...
You just need to put it all inside of a case statement.
so after you run rem, you have another vector, which you called "x" above
for r=1:length(x)
if x(r)<0
x(r)=0;
elseif x(r)>0 && x(r)<1
x(r)=floor(x(r));
else
x(r)=ceil(x(r))...
I'm having trouble on this same problem. Now I'm not 100% sure, but for the initial angular momentum, aren't you supposed to calculate the angular momentum of the package as a separate particle rotating about the same axis.
you have:
I*ωi + R*m*v1(=0)*cos(theta) = I*ωf + R*m*v2*cos(theta)
Do...
alright. But, I'm having trouble calculating the kinetic energy since this is for a real system whereas the other value i calculated was the velocity for the point-particle system.
Homework Statement
Tarzan, whose mass is 110 kg, is hanging at rest from a tree limb. Then he let's go and falls to the ground. Just before he let's go, his center of mass is at a height 3.0 m above the ground and the bottom of his dangling feet are at a height 2.0 above the ground. When he...
You're talking about the centerpoints of the rod? if so they would just be L/2, but how would you put that into a useful form to fit the equation for both axes?
I'm working on this same problem and I can't make heads or tails of what's being asked. The explanation doesn't seem very clear, so if it makes sense to somebody please explain what they're asking for.