Rotational Speed of a Space Station

AI Thread Summary
The discussion focuses on calculating the center-of-mass velocity and rotational speed of a space station after a package is launched from it. The initial angular momentum principle is applied, with the moment of inertia defined as I = MR^2. Participants express confusion over the correct derivation of the final angular speed (ωf) and whether to include the angular momentum of the package as a separate particle. There is debate about the necessity of using cos(theta) in the calculations to account for the angular speed of the space station. Overall, the conversation highlights the complexities involved in applying angular momentum principles to this scenario.
guitarman
Messages
22
Reaction score
0

Homework Statement


Space Station
A space station has the form of a hoop of radius R, with mass M. Initially its center of mass is not moving, but it is spinning with angular speed ω0. Then a small package of mass m is thrown by a spring-loaded gun toward a nearby spacecraft as shown; the package has a speed v after launch.

(a) Calculate the center-of-mass velocity of the space station (vx and vy) and its rotational speed ω after launch. Do not worry about italics. For example, if a variable R is used in the question, just type R. To specify the angle θ simply use the word theta. Likewise, for ω0 use the word omega0.
vx =


vy =


ω =



Homework Equations


vx = (m/M)(-v)cos(theta)

vy = (m/M)(-v)sin(theta)


The Attempt at a Solution



I know that I must use the angular momentum principle, and that the component is out of the page (+z)
I*ωi + R*m*v1(=0)*cos(theta) = I*ωf + R*m*v2*cos(theta)
I = MR^2
so ωf = ωi - R*m*v2*cos(theta)/(MR^2)
Can somebody please let me know where I am going wrong in my derivation of ωf because apparently this is wrong, yet my book does not have any solutions.
 
Physics news on Phys.org
I know that I must use the angular momentum principle, and that the component is out of the page (+z)
I*ωi + R*m*v1(=0)*cos(theta) = I*ωf + R*m*v2*cos(theta)
I = MR^2
so ωf = ωi - R*m*v2*cos(theta)/(MR^2)
Can somebody please let me know where I am going wrong in my derivation of ωf because apparently this is wrong, yet my book does not have any solutions.
I'm having trouble on this same problem. Now I'm not 100% sure, but for the initial angular momentum, aren't you supposed to calculate the angular momentum of the package as a separate particle rotating about the same axis.

you have:
I*ωi + R*m*v1(=0)*cos(theta) = I*ωf + R*m*v2*cos(theta)

Do you think that it should something like this:
(M*R^2)*omega0 + (m*R^2)*omega0=(M*R^2)*omegaf + R*m*v(are you sure that you multiply this times cos(theta)?)

I don't think this is completely right, but it might be a start.
 
Don't you need to use cos(theta) to take into account for the angular speed of the space station?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top