Recent content by gunitsoldier9

Nope, no luck. Beginning to think there is a mistake with the problem

U= 1/2(E0A/d)V2=(1/2)(8.85*10-12*.041m/.002m)*5602=28.4 microjoules Same thing for part b but with the new the new d U= 1/2(E0A/d)V2=(1/2)(8.85*10-12*.041m/.0041m)*5602 = 13.9 microjoules but its wrong

Homework Statement A parallel-plate capacitor has plates with an area of 410 cm^2 and an air-filled gap between the plates that is 2.00 mm thick. The capacitor is charged by a battery to 560 V and then is disconnected from the battery. a.How much energy is stored in the capacitor? b.The...

Yeah thanks. I wish that they would actually draw a picture in the book and point it out.

i think its yz. its really hard to visualize the plane in 3 dimensions and my book doesn't even talk about 3 dimensions for that equipential surfaces

no they cant. so does that rule out the xy plane

I know that its perpendicular to the eclectic field but it just doesn't make sense if the electric field is on the x-axis i know the equipotential surface would be vertical. but i just don't get what plane it would be parallel to.

would that make it xy because a z would mean 3 dimensions are involved.

Homework Statement Consider a region in space where a uniform electric field 6700 N/C points in the negative x direction. What is the orientation of the equipotential surfaces? a.Parallel to the xz-plane. b.Parallel to the yz-plane. c.Parallel to the xy-plane. Homework Equations...