*A little bump* :-)
P.s. I meant ∆H(vap.) at 100 deg. celsius to be 46.2 kJ/ mol
Edit:
Tried: ∆H-T∆S<0
Foumd ∆H to be 46200 J/mol, and T=373,15 K. Gives me that;
46200J/mol - 373,15K*∆S<0
123.8 J/(mol*K)>∆S.
Still does not make any sense! Really confused.
Homework Statement
"From the boiling point you found of ∆H(vaporization) at a 100 degrees celsius, find ∆S(vaporization) at 100 degrees celsius from the formula given (see eqn.)
This is for water.
Homework Equations
∆H-T∆S<0
The Attempt at a Solution
From the task before, I found ∆H(vap.)...
Homework Statement
Got an assignment from the teacher to present a problem I have made by myself and show how I have done it, so I have no answer to refer to in this particular question. Anyways,
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