Recent content by haiku11

This is one of the questions on a small exercise but I don't understand it. I thought that the Earth is in orbit because the mass of the Earth and the Sun combine perfectly such that the orbital velocity is exactly the same as the pull of the sun so the Earth is forever falling towards it. If...

Darn it I forgot the acceleration is negative in this case, this changes everything. Thanks.

On the surface of the sun the acceleration due to gravity is approx 0.25km/s². A mass of gas forming a solar prominence rises from the sun's surface. If only gravity is considered, what must its initial upward velocity be, if it is to reach a height of 24000km above the surface? I can't...

What do you mean? Would 2 dt become a single term? -ln|1+2t| + 2t + C is supposed to be the antiderivative s(t) and the following is solving for C at s(0). I thought it's only if n is not -1 because then it would become x^0 / 0, then you have to use ln|x|? Sorry I missed a lot of things...

Oh I forgot to say √ is supposed to be the integration symbol.

Homework Statement v(t) = (-2 / (1 + 2t)) + 2 I must find the antiderivative s(t) such that s(0) = 5. The Attempt at a Solution u = 1 + 2t du/dt = 2 dt = du/2 √(-2 / (1 + 2t dt)) + 2 =√(-2u^-1 du/2) + 2 =√(-u^-1 du) + 2 = -ln|1+2t| + 2t + C At t = 0 -ln(1 +...

10N force acting in the direction of the vector (1, 1) moves an object from P (-2, 1) to Q (5, 6), calculate the work done. The Attempt at a Solution I can do this question correctly except I only know how to do it using decimals but the answer is in exact values of 60√2J. I can't figure out...

Please Help!

Oh ok that makes a lot more sense. Thanks so much for your help. Edit: I didn't see the rest of the question and now I'm even more confused. I edited the original post to show the entire question.

Homework Statement I have to find the antiderivative of 4/(1+2x)² New question: Find s(t) 2. Given variables and equations a(t) = 4/(1+2x)² v(0) = 0 s(0) = 5 The Attempt at a Solution ∫4(1+2x)-2 = 4∫(1+2x)-2 = 4[(1+2x)-1/-1] = -4/(1+2x) But the correct answer has a -2...