Find velocity required to reach a certain height given only height and gravity

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SUMMARY

The discussion centers on calculating the initial upward velocity required for a mass of gas to reach a height of 24,000 km above the surface of the sun, where the acceleration due to gravity is approximately 0.25 km/s². The equations of motion are derived, leading to the quadratic equation 0 = 0.125t² + Ct - 24000. A critical insight is that the acceleration should be treated as negative when considering upward motion against gravity, which significantly alters the calculations. The correct initial velocity, accounting for this negative acceleration, is approximately 109 km/s.

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haiku11
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On the surface of the sun the acceleration due to gravity is approx 0.25km/s². A mass of gas forming a solar prominence rises from the sun's surface. If only gravity is considered, what must its initial upward velocity be, if it is to reach a height of 24000km above the surface?

I can't figure out how to do this, I have:
a(t) = 0.25 the integral would give me:
v(t) = 0.25t + C the integral of this would give me:
s(t) = 0.125t² + Ct + D

I'm assuming D would be 0 because that's where the prominence starts on the ground so the equation becomes:
24000 = 0.125t² + Ct
0 = 0.125t² + Ct - 24000

I don't know where to go from here because there are 2 variables and I can't do any substitution using the previous equations. Trying to use the quadratic formula made everything really messy when trying to rearrange it in terms of "t". I even tried doing this the physics way although this is a calculus problem and I still couldn't do it with the 5th motion equation because I would be trying to take the square root of a negative. But if I ignore the negative and take the root I get the approximately right answer of around 109km/s.
 
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haiku11 said:
On the surface of the sun the acceleration due to gravity is approx 0.25km/s². A mass of gas forming a solar prominence rises from the sun's surface. If only gravity is considered, what must its initial upward velocity be, if it is to reach a height of 24000km above the surface?

I can't figure out how to do this, I have:
a(t) = 0.25 the integral would give me:
v(t) = 0.25t + C the integral of this would give me:
s(t) = 0.125t² + Ct + D

I'm assuming D would be 0 because that's where the prominence starts on the ground so the equation becomes:
24000 = 0.125t² + Ct
0 = 0.125t² + Ct - 24000

I don't know where to go from here because there are 2 variables and I can't do any substitution using the previous equations. Trying to use the quadratic formula made everything really messy when trying to rearrange it in terms of "t". I even tried doing this the physics way although this is a calculus problem and I still couldn't do it with the 5th motion equation because I would be trying to take the square root of a negative. But if I ignore the negative and take the root I get the approximately right answer of around 109km/s.

If you are taking s positive upward, your acceleration should be towards the sun, therefore negative. Also, as another hint, what do you know about the velocity when it is at maximum height of 24000?
 
Darn it I forgot the acceleration is negative in this case, this changes everything. Thanks.
 

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